Exponential Growth and Decay<\/p>\n
Student\u2019s Name<\/p>\n
Name of Institution<\/p>\n
\u00a0<\/p>\n
\u00a0<\/p>\n
Date of submission<\/p>\n
Exponential Growth and Decay<\/p>\n
Create a story problem that uses either exponential growth or exponential decay. \u00a0<\/p>\n
In 2009, there were 10000 smart phone users in the market.\u00a0 The number of users has increased by 91% per year after to date.\u00a0 How many smart phone users are in the market today?<\/p>\n
This is an exponential growth and as such, the following formula applies:<\/p>\n
y = a (1+r) x<\/p>\n
where y = number of manual \/ hands<\/p>\n
a\u00a0= initial amount before measuring decay = 10000<\/p>\n
r = decay rate (often a percent) = 91%<\/p>\n
x = number of time intervals that have passed = 5<\/p>\n
y then becomes<\/p>\n
y = 10000 (1+0.91)5<\/p>\n
y = 10000 (1.91)5<\/p>\n
y = 10000 * 25.419<\/p>\n
y = 250,000 because people cannot be considered in their fractions.<\/p>\n
Problem to solve:\u00a0Story Problem:\u00a0 Due to enhancements in technology and automation, the manual hands on jobs at a firm which currently numbers 2500 is decreasing a rate of 20% per year.\u00a0 What is the number of manual hands on jobs left after 3 years?<\/p>\n
This is an exponential decay and as such, the following formula applies:<\/p>\n
y = a (1-r) x<\/p>\n
where y = number of manual \/ hands<\/p>\n
a\u00a0= initial amount before measuring decay = 2500<\/p>\n
r = decay rate (often a percent) = 20%<\/p>\n
x = number of time intervals that have passed = 3<\/p>\n
y then becomes<\/p>\n
y = 2500 (1-0.2)3<\/p>\n
y = 2500 (0.8)3<\/p>\n
y = 2500 * 0.512<\/p>\n
y = 1280<\/p>\n","protected":false},"excerpt":{"rendered":"
Exponential Growth and Decay Student\u2019s Name Name of Institution \u00a0 \u00a0 Date of submission Exponential Growth and Decay Create a<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-48973","post","type-post","status-publish","format-standard","hentry"],"yoast_head":"\n