Name <\/p>\n
Professor <\/p>\n
Course <\/p>\n
Date <\/p>\n
MANF<\/p>\n
Q14) From the mean of and the total mumbe of trimming, it is healthy to say that the two operatiors are nkt tromining of the same part. The numbwer of parts trimmed by MARY IS 13.1668, while the total number of trimming done by jack is 13.0815. this is to say that ,ary is mr eficienty at trimming than jack. On the other hand, JACLS HISTOGgram is skewed postively while that of mary is not normaly dustributed. Sufice to day that the CPC, CPK control chrt Of jack is nt stable<\/p>\n
Question number 15)<\/p>\n
Observed Expected Z<\/p>\n
PPM<LSL 0.0 0.2 -5.119<\/p>\n
PPM>USL 0.0 2.7 4.550<\/p>\n
PPM 0.0 2.8 % Defects 0.0 0.0 According to the data provided form the CNC turning centre, the level of production is negatively skewed, the standard deviation is 0.006<\/p>\n
Decimal Points 3.000<\/p>\n
Unit of Measure 0.001<\/p>\n
Number of Entries 30<\/p>\n
Average 0.012<\/p>\n
Stdev 0.006<\/p>\n
Median 0.011<\/p>\n
Mode 0.020<\/p>\n
Minimum Value 0.002<\/p>\n
Maximum Value 0.020<\/p>\n
Range 0.018<\/p>\n
LSL -0.020<\/p>\n
USL 0.040<\/p>\n
Number of Bars 5.000<\/p>\n
Number of Classes 4.000<\/p>\n
Class Width 0.005<\/p>\n
Beginning Point -0.025<\/p>\n
Stdev Est 0.006<\/p>\n
d2\/c4 1.128<\/p>\n
Target 0.01<\/p>\n
..<\/p>\n
Cp 1.611<\/p>\n
Cpk 1.517<\/p>\n
CpU 1.517<\/p>\n
CpL 1.706<\/p>\n
Cpm 1.683<\/p>\n
Cr 0.621<\/p>\n
ZTarget\/\uf044Z 0.311<\/p>\n
Pp 1.763<\/p>\n
Ppk 1.659<\/p>\n
PpU 1.659<\/p>\n
PpL 1.866<\/p>\n
Skewness -0.009<\/p>\n
Stdev 0.006<\/p>\n
Min 0.002<\/p>\n
Max 0.020<\/p>\n
Z Bench 4.538<\/p>\n
% Defects 0.0%<\/p>\n
PPM 0.000<\/p>\n
Expected 2.841<\/p>\n
Sigma 6.040<\/p>\n
Q 17) data x=16 minutes, S=3 minutes, R=7 minutes., duration 320 daya ,, sample 5<\/p>\n
X charts UCL=16+3X7=37<\/p>\n
LCL=16-3X7=-4<\/p>\n
R charts =UCL=>9X7=63<\/p>\n
LCL=>9-7=2<\/p>\n
Q#18) According to the x chart , the process isn perfectly in ocntrol, as the conyrol level is just within the nmargin of safety of tye upper contrio limit and the lower control limit, from the x chrat, is is open that mlost of the points are close to the average, while a few points occur near the control limits. Additionally, there are No points beyond the control limits. This is a sin of a process within the control limit. howevwe, from the r charts, the process is not stable . The R charts shows that the process was highly variable . never thelss, if the avarage fill is 50.0 pound, that wil be slihtly above the process, and so out of the process control. However, the variability of the process will accommodate that thouh not stable .<\/p>\n
Q#19) The pltted avarages and ranges shows that the thermometers produced in te factory are conforming to the oreset control limts, most of the thermometers have a very hih level of [recision as their data appear close to the controllimit. The process on the other hand is variable as there are some process that are closer to the lower control limit. <\/p>\n
X chart<\/p>\n
R Charts<\/p>\n","protected":false},"excerpt":{"rendered":"
Name Professor Course Date MANF Q14) From the mean of and the total mumbe of trimming, it is healthy to<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-39692","post","type-post","status-publish","format-standard","hentry"],"yoast_head":"\n